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Kit Nat-Herb | Pomada 110g+Loción

(29 valoraciones de clientes)

El precio original era: $115000.El precio actual es: $105000.

Kit Nat-Herb

Contiene:

1 Loción de cannabis

1 Pomada de 110gr

Disponible para reserva

Kit Nat-Herb

Contiene:

1 Loción de cannabis

1 Pomada de 110gr

Descripción:

Formulas diseñadas para coadyuvar a humectar, nutrir, relajar y como anti oxidante para el acondicionamiento de la piel a través del efecto emoliente del cannabis y sus otros componentes naturales.

Peso 1000 g
Dimensiones 30 × 30 × 30 cm

29 valoraciones en Kit Nat-Herb | Pomada 110g+Loción

  1. Sang

    how to take dianabol first cycle

    References:

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  2. Leandro

    With 3-5g per day, expect leads to 3-4 weeks as your muscles steadily reach full saturation. Nonetheless, your muscle tissue will eventually
    attain full saturation both way. It takes about three weeks to fully
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    And as all the time, it’s vital to take heed to your physique and
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    References:

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  4. Sandy

    ipamorelin blood pressure raise

    References:

    cjc-1295 ipamorelin itching, https://git.partners.run/,

  5. Lynwood

    The Heart Of The Internet

    Long Term Side Effects of CJC‑1295/Ipamorelin

    CJC‑1295 is a synthetic growth hormone releasing peptide that stimulates the pituitary to release growth hormone (GH), while Ipamorelin is a ghrelin receptor agonist that further boosts GH secretion. Together
    they are often used in bodybuilding, anti‑aging protocols and
    research settings. Although short‑term use has been reported to produce increased
    muscle mass, improved sleep quality and better recovery,
    the long‑term safety profile remains less well understood.
    Below we outline the most commonly reported side effects, potential mechanisms behind them, and what current evidence suggests about chronic exposure.

    Hormonal Imbalance

    Both peptides act on the pituitary axis. Prolonged stimulation can lead to downregulation of endogenous
    GH production or a rebound suppression once therapy stops.
    Patients may experience fatigue, loss of muscle tone, or decreased libido as their own hormone levels normalize.
    In rare cases, persistent elevation in insulin‑like growth factor‑1 (IGF‑1) has been linked to increased risk of certain cancers and
    metabolic complications.

    Edema and Water Retention

    GH promotes sodium retention and fluid accumulation. Users who continue CJC‑1295/Ipamorelin for months often report puffiness, especially around the ankles and
    face. This edema can be uncomfortable and may mask underlying cardiovascular issues if
    not monitored by a clinician.

    Insulin Resistance and Metabolic Disturbances

    Elevated IGF‑1 levels influence glucose metabolism. Chronic use has been associated with transient insulin resistance, elevated
    fasting glucose, and in some individuals, the development of type 2 diabetes mellitus over time.
    Regular blood tests for HbA1c and fasting glucose are advised during
    long‑term treatment.

    Joint Pain and Tendonitis

    Growth hormone increases collagen turnover and can alter joint cartilage metabolism.
    Some long‑term users describe chronic knee or shoulder pain that correlates with the duration of therapy, possibly due to accelerated tissue remodeling or subtle overuse injuries.

    Cardiovascular Effects

    While short‑term GH therapy has been shown to improve lipid profiles,
    prolonged exposure may lead to left ventricular hypertrophy in susceptible individuals.
    Continuous monitoring via echocardiography
    is recommended for those on extended courses.

    Psychological and Cognitive Changes

    Reports of mood swings, irritability, or mild depression have emerged among long‑term users.
    The mechanism may involve altered neurotransmitter levels driven by GH’s influence on brain tissue.
    A mental health check can help distinguish these effects from underlying conditions.

    Immune Modulation

    GH has immunomodulatory properties; chronic elevation could dampen natural immune surveillance.
    Some studies suggest an increased incidence of infections or a
    slower wound‑healing process in long‑term users,
    though data remain limited and further research is needed.

    Regulatory and Legal Considerations

    The long‑term use of CJC‑1295/ipamorelin side effects women outside clinical trials
    is not approved by major regulatory bodies such as the FDA
    or EMA. Users risk legal penalties, and pharmacies may refuse to dispense these peptides for extended
    periods. Compliance with local laws is essential.

    In summary, while CJC‑1295/Ipamorelin can offer significant benefits for muscle
    growth and recovery, long‑term use introduces a spectrum of potential side effects ranging from hormonal dysregulation to metabolic and cardiovascular complications.
    Regular monitoring by healthcare professionals, adherence to dosage guidelines, and an awareness of emerging research are critical safeguards for anyone considering extended therapy.

    Top Posts

    The following articles have garnered the most readership within the community of peptide enthusiasts and
    researchers. These pieces provide a comprehensive look at protocols, safety data, and user experiences
    that help shape informed decisions about growth hormone releasing peptides.

    «Understanding Growth Hormone Release: Mechanisms and Clinical Applications» – This post breaks down how peptides such
    as CJC‑1295, Ipamorelin, and others influence the pituitary axis, providing
    a clear pathway from molecular action to therapeutic outcomes.

    «Safety First: Monitoring Protocols for Long‑Term Peptide Use» – A practical guide that outlines recommended blood tests, imaging studies,
    and lifestyle adjustments necessary to mitigate risks associated
    with chronic peptide therapy.

    «User Experiences: Success Stories and Cautionary Tales» – An aggregated collection of first‑hand accounts from
    athletes and bodybuilders who have used CJC‑1295/Ipamorelin over several years, highlighting both benefits and side effects observed
    in real‑world settings.

    «Regulatory Landscape for Peptide Therapies Worldwide» – A detailed overview of how different countries regulate peptide use, including licensing
    requirements, legal restrictions, and the impact on accessibility for researchers and clinicians.

    «Comparative Analysis: CJC‑1295 vs. Sermorelin vs. GHRP‑6» – This article compares the pharmacodynamics, efficacy, and safety
    profiles of three popular growth hormone releasing peptides,
    helping readers choose the best option for their
    goals.

    These top posts serve as essential resources for anyone navigating the complex
    world of peptide supplementation, offering evidence‑based insights,
    community wisdom, and practical tools for safe usage.

  6. Donte

    Anavar For Men: The Ultimate Dosage Guide For Bodybuilding

    Anavar for Men: The Ultimate Dosage Guide for Bodybuilding

    Anavar (oxandrolone) is one of the most popular anabolic steroids among male bodybuilders due to its reputation for delivering lean muscle gains while
    minimizing water retention and fat gain. This guide compiles everything you need to know—from basic science and dosage ranges to cycle planning,
    side‑effect management, and post‑cycle recovery.

    Key Takeaways

    Dosage ranges vary by goal: cutting (5–20 mg/day), bulking (10–30 mg/day).

    Cycle length typically 4–6 weeks; longer cycles increase risk of suppression.

    Post‑cycle therapy (PCT) is essential, especially after doses
    above 15 mg/day or when combined with other steroids.

    Liver support (milk thistle, N-acetylcysteine) and regular blood work help
    mitigate hepatotoxicity.

    Legal considerations: Anavar is a controlled substance
    in many countries; obtain it through reputable sources only.

    Understanding Anavar: What Is Oxandrolone?

    Oxandrolone is a synthetic derivative of dihydrotestosterone (DHT).
    Developed in the 1960s for medical use—such as aiding
    weight gain after surgery or illness—it has since
    become a staple for athletes seeking high strength with minimal bulk.
    Its chemical structure allows it to bind strongly to androgen receptors while being less aromatizable,
    which reduces estrogenic side effects like gynecomastia.

    How Anavar Works: The Science Behind the Results

    Anavar increases protein synthesis by enhancing the translation of
    mRNA into amino acids that build muscle fibers. It also improves nitrogen retention and glucose uptake
    in muscle cells, facilitating faster recovery after training.
    Because it has a short half‑life (≈9 hours) and low aromatization, users experience quick
    peaks with fewer estrogenic complications.

    Anavar Dosage for Men Bodybuilding

    General Recommendations

    Goal Typical Daily Dose Duration

    Cutting 5–20 mg/day 4–6 weeks

    Bulking (light) 10–30 mg/day 4–6 weeks

    Advanced stacking 20–40 mg/day (combined with other agents) 6–8 weeks

    Notes:

    Start at the lower end if you are new or have a low tolerance.

    Avoid exceeding 30 mg/day unless under close medical supervision.

    Medical Dosage Information for Oxandrolone

    In clinical settings, oxandrolone is prescribed at:

    5–10 mg/day for weight gain in patients with severe burns or trauma.

    2.5–5 mg/day to treat bone loss in men receiving radiation therapy.

    These doses are well below the typical bodybuilding range and underscore how much more
    potent Anavar can be when used recreationally.

    Anavar Dosage for Men Cutting

    For cutting, the focus is on preserving lean muscle while shedding fat:

    Low dose (5–10 mg/day): Ideal for beginners or those prone to side effects.

    Moderate dose (15–20 mg/day): Common among intermediate lifters; yields
    noticeable strength gains without significant water retention.

    Pre‑Cycle Preparation: Setting Up for Success

    Baseline Blood Work – Liver enzymes, lipid profile, testosterone,
    estradiol, and PSA.

    Nutrition Plan – High protein (1–1.5 g per pound of bodyweight), moderate carbs to fuel training, controlled calories to support cutting or bulking
    goals.

    Training Regimen – Structured split focusing on progressive overload; incorporate both hypertrophy sets (8‑12
    reps) and strength phases (4‑6 reps).

    Supplement Stack – Creatine monohydrate, BCAAs,
    whey protein, multivitamin, omega‑3 fatty acids.

    Understanding Anavar Cycle Length for Men

    Because Anavar has a short half‑life, a 4–6 week cycle
    is sufficient to achieve gains while limiting the duration of hormonal suppression. Extending
    beyond 8 weeks without PCT can lead to prolonged testosterone shutdown and increased side‑effect risk.

    Drug Interactions: What Not to Mix with Anavar

    Aromatase inhibitors (anastrozole, letrozole): Generally unnecessary due to low
    aromatization; may cause estrogen deficiency.

    Stimulants: Combining high doses of stimulants with Anavar can strain the cardiovascular system.

    Other anabolic steroids: Stacking with testosterone or growth hormone increases suppression risk
    and should be paired with robust PCT.

    Understanding Anavar and Testosterone Relationship

    Anavar stimulates muscle protein synthesis but does
    not directly boost endogenous testosterone production. After a
    cycle, testosterone levels often drop below
    baseline due to negative feedback on the hypothalamic‑pituitary‑gonadal
    axis. This necessitates careful PCT (clomiphene or tamoxifen) to restore natural hormone production.

    Anavar Clen Cycle for Men

    A common stack:

    Anavar 10–20 mg/day

    Clenbuterol 5 mcg twice daily

    This combination enhances fat loss while preserving muscle.
    Monitor heart rate and blood pressure closely; clenbuterol can cause palpitations.

    Anavar and Winstrol Cycle Optimal Dosage

    Stacking with Winstrol (stanozolol) amplifies cutting effects:

    Anavar 10–15 mg/day

    Winstrol 5–10 mg/day

    Duration: 4 weeks. Both agents are potent aromatase inhibitors; keep an eye on estrogen‑related
    symptoms.

    Anavar and Testosterone Cycle for Men

    A typical stack:

    Testosterone enanthate 250 mg every two weeks

    Anavar 20 mg/day

    This pairing balances muscle growth with anabolic support, reducing the risk of testosterone suppression. Ensure PCT includes a selective estrogen receptor modulator (SERM)
    to reactivate natural production.

    Anavar Only Cycle for Men

    For those who prefer minimal stacking:

    5–10 mg/day (low dose) or

    15–20 mg/day (moderate dose)

    Duration: 4 weeks. Ideal for novice users or as a «maintenance» cycle during cutting phases.

    Anavar Dosage for Weight Loss

    Anavar’s lipolytic properties are modest; combine with:

    Low-carb diet

    High-intensity interval training (HIIT)

    Dosage: 10–15 mg/day over 4 weeks. Expect increased lean mass and a slight boost in basal metabolic rate.

    Liver Support and Blood Work Monitoring

    Milk thistle (silymarin) 200 mg twice daily

    N-acetylcysteine 600 mg thrice daily

    Liver panel: ALT, AST, ALP every 2–3 weeks

    Adjust supplements if enzymes rise above 1.5× the upper limit of normal.

    Side Effects: What Men Actually Experience

    Symptom Frequency (low dose) Frequency (high dose)

    Acne Common Very common

    Hair loss Rare Possible if genetically predisposed

    Mood swings Occasional Frequent

    Elevated blood pressure Unlikely Possible

    Liver enzyme elevation Mild Moderate to severe

    Most side effects are reversible with proper dosing and PCT.

    Post‑Cycle Therapy: The Non‑Negotiable Recovery Phase

    PCT – Clomiphene 50 mg/day or tamoxifen 20 mg/day
    for 4–6 weeks.

    Dietary protein – Continue high protein intake to support
    recovery.

    Rest – Avoid heavy training for the first
    2–3 weeks post‑cycle.

    Blood work – Repeat liver panel and hormone profile after PCT completion.

    Understanding Testosterone Suppression and Recovery

    Suppression occurs because exogenous steroids reduce LH secretion, cutting natural testosterone production.
    Recovery time varies:

    Low dose (≤10 mg/day): 2–3 weeks

    High dose (>20 mg/day): 4–6 weeks or longer

    PCT accelerates this process and prevents long‑term hypogonadism.

    Diet and Training During Anavar Cycles

    Nutrition:

    Protein: 1.2–1.5 g per pound bodyweight

    Carbs: Adjust to caloric needs (higher for bulking, lower
    for cutting)

    Fats: 20–30% of total calories

    Training:

    Bulking cycles: Focus on heavy compound lifts (squats, deadlifts) with hypertrophy sets.

    Cutting cycles: Incorporate HIIT and moderate volume to preserve muscle while promoting fat loss.

    Navigating Legalities and Sourcing Safely

    In the U.S., Anavar is a Schedule III controlled substance; possession without prescription can lead to legal consequences.

    Verify that suppliers are reputable, offer lab‑tested products, and
    provide certificates of analysis.

    Avoid «bulk» packages that may contain contaminants or counterfeit oxandrolone.

    Debunking Common Anavar Myths

    «Anavar is safe because it’s mild.»

    It still suppresses testosterone and can affect liver enzymes.

    «You don’t need PCT after a 4‑week cycle.»

    Even short cycles can cause hormonal suppression; PCT is recommended
    if doses exceed 10 mg/day.

    «Anavar causes significant estrogenic side effects.»

    Its low aromatization makes this rare, but monitoring is still advised.

    What Experts Say About Anavar for Men

    Sports endocrinologists emphasize the importance of hormone monitoring and PCT.

    Professional bodybuilders cite anavar and winstrol cycle optimal dosage’s efficiency in cutting phases due to minimal water retention.

    Medical researchers highlight its therapeutic use for wasting diseases, underscoring a strong safety profile
    when dosed appropriately.

    Frequently Asked Questions

    How fast do results show on Anavar?

    Strength gains can appear within 2–3 weeks, while visible lean muscle improvements may take 4–6 weeks.

    Can I take 10 mg Anavar daily?

    Yes, 10 mg/day is a common low‑dose regimen for cutting and beginners.

    Avoid exceeding this without medical guidance.

    Why run Anavar cycles for 6 weeks?

    A 6‑week cycle maximizes anabolic effects while keeping
    the suppression window manageable; many
    users find 4 weeks insufficient for desired
    gains.

    Do I need PCT after 4 weeks of Anavar?

    If you’ve taken above 10 mg/day, a short PCT (2–3 weeks)
    is advisable to restore natural testosterone production.

    What’s the best way to take Anavar for maximum absorption?

    Take it with a carbohydrate source or a light meal; absorption peaks
    within 1–2 hours. Splitting the dose into two smaller servings can help maintain steady blood levels.

    Can I drink alcohol while on Anavar?

    Alcohol may further stress the liver and
    increase estrogenic side effects. Limit intake to occasional, moderate amounts if
    at all.

    Medical Considerations for Anavar Usage

    Pre‑existing liver disease: Contraindicated due to hepatotoxic
    potential.

    Cardiovascular risk: Monitor blood pressure and lipid profile; avoid
    high doses if hypertension is present.

    Hormonal disorders: Consult an endocrinologist before use.

    Understanding Anavar’s Mechanism of Action

    Anavar binds androgen receptors, initiating transcriptional changes that upregulate muscle protein synthesis.
    Its structure also inhibits proteolysis by downregulating ubiquitin‑proteasome pathways, thus preserving existing muscle tissue during caloric
    deficits.

    Long-Term Effects and Safety Profile

    Long‑term use (beyond 8–12 weeks) is associated
    with:

    Endogenous testosterone suppression lasting months.

    Potential liver enzyme elevation, reversible
    upon cessation.

    Psychological changes such as mood swings, especially
    at higher doses.

    When used responsibly within recommended limits and coupled
    with proper monitoring, Anavar remains one of the
    safest anabolic agents for male athletes.

    Read Also

    Understanding Ipamorelin Side Effects: A Comprehensive Review

    Dianabol Cycle: How To Take, Risks And Benefits Guide

    Comprehensive BPC‑157 Guide: Benefits, Safety, Dosage &
    More

    Dianabol Tablets: Complete Guide For Bodybuilders On Price

    Anavar Results: Complete Timeline, Safe Dosing & Cycle Protocols for Maximum Gains

    Dianabol Real Before & After Results, Timing Secrets, and Critical Safety
    Protocols

    Anavar Cycle Mastery: Science‑Backed Dosage,
    Stacking & Results

    Peptide Therapy: Muscle Growth, Recovery & Anti‑Aging Complete Guide

    Augmented NAC: Enhanced Absorption, Antiviral Benefits
    & Safe Use for Bodybuilders

    CJC‑1295 and Ipamorelin: Guide to Muscle Growth, Fat Loss & Recovery Real
    Results

    Ipamorelin vs Sermorelin: Benefits, Dosage & Blends for Bodybuilders

    KPV Peptide: The Real Deal on Gut Healing, Inflammation Control & Safe Usage

  7. Maynard

    The Heart Of The Internet

    The Heart Of The Internet

    In the digital age, information travels faster than ever before.

    One of the most compelling stories that has captured public imagination revolves around the world of professional bodybuilding and the hidden realities behind the gleaming physiques seen on television and in magazines.
    At first glance, the discipline appears to be a purely scientific pursuit:
    rigorous training, meticulous nutrition, and an unwavering commitment to health.
    Yet beneath the surface lies a more complex narrative about performance enhancement and the pressures athletes face.

    In‑Depth Look: The Bodybuilding World

    A Glimpse of the Industry

    Professional bodybuilding is not just a sport—it’s
    a cultural phenomenon that draws millions of fans worldwide.
    The athletes are known for their extreme muscle mass, low body fat, and incredible
    symmetry. They train daily in multiple sessions,
    often exceeding 10–12 hours per week, and follow strict diet plans.

    The Role of Performance Enhancers

    One key factor that fuels the extraordinary physiques is the
    use of performance‑enhancing drugs (PEDs).
    These substances can range from anabolic steroids to growth hormones
    and other supplements. While some athletes may try to avoid PEDs, others rely on them to gain an edge over competitors.

    Legal Issues Surrounding PED Use

    The legal status of these substances varies across countries.
    In many places, the possession or use of certain drugs is regulated by
    law. Athletes who are caught using illegal substances face serious consequences—such as bans
    from competitions and criminal charges in some jurisdictions.

    We need to analyze which text uses more words that start with letter
    T. That means we count all words starting with «T»
    (case-insensitive). We must also consider words like «the», «to», «they», «through», etc.

    But we need the total number of such words in each text.
    Then compute the percentage relative to total word count?
    Actually they ask: «Which text uses a higher percentage of words that start with the letter T.» So it’s
    about percentages.

    So we need to compute for each text:

    Total number of words (maybe ignoring punctuation)

    Number of words starting with T

    Compute ratio (#words starting with T) / total words 100%.

    We also must consider the instruction: «If a word starts with ‘t’ or ‘T’, count it.» So
    case-insensitive. Also we should ignore hyphens and apostrophes?

    Eg «don’t» maybe counts as «dont»? Actually it’s
    considered one word, starting with d, not t.

    Also we need to decide about words that are only punctuation: e.g., «…» might
    be considered a word? Usually no; but if we treat tokens separated by whitespace and punctuation removed.
    We can implement a function: given text string,
    split on whitespace, then for each token, strip leading/trailing punctuation characters (like .,?!:
    ;»‘()- etc) maybe also trailing quotes. But hyphen inside might cause splitting? Eg «co-operate» would be considered as single word starting with c; but we might want to treat hyphen as part of word or split into two words? The instructions: «Consider the entire text, including any punctuation and special characters.» So we should not split on hyphen because it’s a character within word. But if we strip leading/trailing punctuation like dash at beginning maybe? Eg «-example» would become «example»? Actually – might be part of word but rarely at start; but if there is something like «—example» (em dash) before example, the dash is not part of word but punctuation preceding the word. So we should strip leading punctuation marks that are not alphabetic and trailing punctuation marks that are not alphabetic. But hyphen inside a word is fine.

    Also digits: we should treat them as characters too; they can be part of string like «123». We might want to keep them as part of words, because they are part of the original string. So if we have «a1b2c3» that’s one word maybe? But we need to decide how to split: we could treat any sequence of alphanumeric characters (including digits) as a word; but also if there are punctuation marks like periods or commas within, we might want to keep them separate? Eg «Hello,world.» -> The words would be «Hello», «,world» maybe? But the problem statement says «split each string into words and then concatenate these words». It doesn’t mention punctuation. So likely the input strings contain only letters (maybe uppercase/lowercase) and no spaces or punctuation. They might have hyphens? But hyphen is considered a word separator? Not sure.

    Given typical tasks, it’s safe to assume that the strings consist of characters ‘a’..’z’, maybe digits. But we need to confirm with examples. Let’s search memory: This problem «Word
    Concatenation» or similar appears on Codeforces as «C. Word Game» but not exactly.

    Another possibility is that the strings may contain digits and
    letters, but no spaces.

    Let’s read the problem statement again:

    «You have N strings. You need to check if any two of them can be concatenated in either order such that the result equals a palindrome. Output ‘YES’ if possible else ‘NO’.»

    It says «In particular, we want to see whether there exist i «ba». b=»cba» not equal to «ba». So a+b= «abcba» indeed palindrome? Let’s verify:

    string: a(0)=’a’, 1=’b’, 2=’c’,3=’b’,4=’a’. Mirror: index0 vs4 both ‘a’, 1 vs3 both ‘b’, center c. Yes it’s palindrome.

    So our earlier claim is false! Because a+b can be palindrome even if b != reverse(a) and lengths differ. For example, «ab» + «cba» = «abcba». Wait but here len(b)=3; a=2; So difference 1; but we had earlier condition that if |a|>|b| then not palindrome. Here a is shorter than b (len 2 S + rev(S) = rev(rev(S)) + rev(S) => S + rev(S) = S + rev(S). So holds! So if one string is reverse of the other, condition holds.

    But there may be also pairs where both strings are palindromes and same? Let’s test: Suppose A=B=palindrome. Condition: A+A = rev(A)+rev(A)=A+A (since palindrome). So holds.

    Also if A= palindrome and B arbitrary? Let’s check: Suppose A palindrome, B arbitrary. Condition: A+B = rev(B)+rev(A). For equality to hold, we need B = rev(B) ??? Wait compute: If A is palindrome then rev(A)=A. The condition becomes A+B = rev(B)+A => subtract A both sides gives B=rev(B), so B must also be palindrome. So indeed both palindromes.

    Thus equality holds iff for each pair (i,j), the strings satisfy some property that ensures equality for all pairs: basically we require that for all i= 1. Thus all strings are powers of same base string w.

    Therefore the set is exactly those where all strings are powers (concatenated copies) of a common base string w. Because if they commute pairwise, then product independent of order: any arrangement yields concatenation of same multiset of powers; but we need to confirm that ordering doesn’t change because w^mi and w^mj commute obviously as they are powers of same w; thus any permutation results in w^m1+m2+… = same final string.

    Thus property reduces to «all strings share a common divisor base string».

    Hence algorithm: For each set, find if there exists a string d such that each word is made by repeating d some integer times. Equivalent to: All words have same length of minimal period (their smallest divisor). But not just same period; they must be powers of the same primitive root.

    We can compute for all words the minimal primitive root using algorithm for computing smallest period. For a string s, we can find its minimal period p by using failure function or prefix function from KMP: let n = len(s); compute longest proper prefix that is also suffix; then minimal period = n – lpsn-1 if divides n else n. But we want the primitive root string of length p repeated times. So we can get s0:p. Then we need to ensure all words share same primitive root string.

    However, there might be case where word A’s primitive root is «ab», word B’s primitive root is «abab» (which has primitive root «ab»). But we would compute for each string its minimal period p. For «abab» length 4, lps3 = 2? Actually longest proper prefix-suffix of «abab» is «ab» length 2; n=4; n%p==0 so p=2 -> root «ab». So both produce same root.

    Thus algorithm: compute minimal period root for each word. If all roots equal, answer YES else NO.

    Edge case: if any string’s root cannot be found? But we always find a root (string itself). So safe.

    But wait: what about strings that are not powers of the same base but still satisfy pairwise conditions? Let’s test potential counterexample by brute force small alphabets to confirm.

    We can write script to generate all strings up to length 4 over alphabet ‘ab’, compute minimal roots and see if pairwise condition holds. But we trust logic.

    Let’s do quick reasoning: Suppose there exist three words A,B,C such that pairwise conditions hold but no common root exists. We found earlier that leads to contradiction: Because if A|B, B|C then A|C (since divisibility transitive). So all pairs must satisfy same direction of divisibility. Thus either all are multiples of some minimal word? Actually we can deduce:

    Let w be the shortest among them. Suppose w = A. Then A divides B and C. Since A is shortest, if A | B then B is a multiple of A. Similarly for C. So A is common divisor. But that doesn’t guarantee it’s also a factor of all. Wait we need common root dividing all? Actually we found earlier: If w divides B and C, then w is common divisor but not necessarily root factor because w might be repeated factor too. However if w is shortest among them, then any other word longer than w may have w as prefix or suffix repeated times. But w could itself be a repetition of some smaller string? But since w is shortest among all words, there can’t be smaller substring dividing w. Thus w must be the minimal root.

    Hence we can choose minimal length word as minimal root? Let’s analyze: Suppose we have words A and B such that each is repeated of some base strings: A = u^k1, B = v^k2. We know they share same set of roots (same collection). So there exists a common minimal string r that divides both A and B, and any other root is a repetition of r. The length of the minimal word among all words must be some multiple of |r|. But can we guarantee that the shortest word equals some power of r? Yes, because each word is a repetition of r; thus their lengths are multiples of |r|. So the shortest word’s length is at least |r| but could be bigger if none of them equal r exactly. However, all words are powers of r; so any word that is shorter than another must still be a power of r with smaller exponent (maybe 1). But we cannot guarantee that there’s a word equal to r because the minimal exponent might be >1 for all words? Wait: Suppose r=2, we have words lengths 4 and 6. Both are multiples of 2; but not multiples of 3? Actually 4=22, 6=23. But there is no word equal to r (length 2). So minimal length among given words is 4. That still is a power of r: 4 = r2. So it’s still some exponent >1.

    But the property we used earlier might rely on using the shortest word as base for gcd computations? We used that the gcd of all lengths equals the gcd of any two lengths. But also we used property that if we have pair (x, y) with x f are representable.

    If g > 1, we can divide by g: let a=L1/g,b=L2/g. Then any integer >= (ab – a – b + 1)g? Actually the Frobenius number scales with g: f = g(ab – a – b). So all multiples of g greater than that are representable. But we need representability for any total length T, not necessarily multiple of g. However if gcd(L_i) > 1, then only lengths divisible by g can be represented. Since our string may have arbitrary length (maybe not divisible by g), but the string itself has a fixed length n. If n is not divisible by g, it’s impossible anyway. But we don’t know n; we need to consider all possible strings that satisfy constraints. Some of those strings might have lengths divisible by g and some might not. So we cannot just ignore gcd.

    But maybe the problem expects that the string length will be such that a representation exists if any solution exists. But it’s safer to handle this.

    We can approach dynamic programming over the set of lengths up to some maximum. Since constraints on positions are up to 100, we only care about those indices. So we can consider all possible strings whose length is at least max(pos). The string length could be greater than that but not needed because there are no constraints beyond that.

    But if the string length is >maxPos, then the string would have characters after that which don’t matter; they can be anything. But they could affect the ability to satisfy the regex: e.g., the regex might require a specific number of ‘a’s or other pattern that depends on the entire string, including trailing characters.

    But we only need to find a minimal length string that satisfies the regex and constraints. If there is no such string with minimal length primobolan dianabol cycle). But if you avoid revisiting a state, you’ll find shortest path in terms of number of transitions? Not exactly: BFS would give shortest by edges; DFS with visited set may not. However, typical algorithm for shortest path on directed graph is Dijkstra/BFS. But here we don’t have weights, so BFS.

    But maybe the question expects: «To find a reachable state from some state, you
    can compute the transitive closure of the reachability relation using standard algorithms like
    DFS or Floyd-Warshall.» And to find all reachable states, run DFS/BFS from that state. The algorithm complexity is O(|states| + |edges|).

    Also they might mention that if you want to compute the set of states reachable in exactly k steps (bounded depth), you can use dynamic programming with adjacency matrix exponentiation.

    Alternatively, maybe they ask about computing all possible reachable states given a set of transitions? They might ask: «Given the state machine graph, how many distinct reachable states exist from each state?» That would be solved by performing BFS and counting nodes visited.

    The question is ambiguous. Let’s read again:

    «Suppose we have an automaton with a graph representing its state transition function. I want to figure
    out which states can reach which other states. How
    can I compute the set of reachable states? What are
    some algorithmic methods for this?»

    We need to answer: Provide algorithmic approach to compute reachability in directed graphs, such as depth-first search (DFS), breadth-first search (BFS), or transitive closure using Floyd-Warshall or repeated squaring. Use adjacency matrix representation and dynamic programming.

    Also mention that we can use standard graph traversal algorithms for each node to find reachable nodes. Complexity: O(V + E) per source, O(V(V+E)) total if repeated.

    Alternatively, compute all-pairs reachability via transitive closure: compute matrix of boolean values; using Floyd-Warshall algorithm: for k from 1..n, for i from 1..n, for j from 1..n, reachableij = reachableij or (reachableik and reachablekj). Complexity O(n^3).

    Also mention that if graph is directed acyclic, we can compute reachability using DP: topological sort; propagate sets.

    Thus answer: Use DFS/BFS from each node; or use Floyd-Warshall to compute transitive closure. Also mention algorithmic complexity: BFS/DFS per node gives O(n(n+m)). Floyd-Warshall O(n^3). For DAG, can do O(n+m) using bitset DP after topological order.

    So answer accordingly.### 1. Problem restatement

    Given a directed graph \(G=(V,E)\) with \(|V|=n\) and \(|E|=m\), for every vertex

    \(v_i\in V\) we want to know which vertices are reachable from it – i.e. the set

    [
    R(v_i)=\,u\in V\mid \textthere is a directed path v_i\leadsto u\,.
    ]

    We need an algorithm that produces all \(R(v_i)\) (or a compact representation of them)
    and we want to discuss how fast this can be done.

    1. Naïve «for‑each‑vertex» DFS/BFS

    For each vertex \(v_i\)

    run DFS/BFS starting from v_i
    record all visited vertices as R(v_i)

    Complexity:

    DFS/BFS costs \(O(|V|+|E|)\). Repeating for every start vertex gives

    [
    T_\textnaïve = |V|\,(|V|+|E|) \;=\; O(|V|^2 + |V||E|).
    ]

    For a dense graph with \(|E|=O(|V|^2)\) this is \(O(|V|^3)\).

    This brute‑force method is simple but far from optimal.

    ——————————————————————–

    2. Optimised Approach – Floyd–Warshall (Transitive Closure)

    The problem of reachability for all pairs can be solved in cubic time
    by computing the transitive closure of the directed graph.
    Floyd–Warshall, originally used for shortest paths, also yields
    the transitive closure when we replace «shortest distance» by
    «is there a path».

    Algorithm

    Let `A` be the adjacency matrix (`1` if edge i→j exists, else `0`).
    For each intermediate vertex `k = 1 … n`

    for i = 1 … n
    for j = 1 … n
    Aij = Aij OR (Aik AND Akj)

    After the loops, `Aij == 1` iff there exists a directed path
    from vertex `i` to vertex `j`.

    Complexity

    Time: The algorithm performs `n` iterations of an `O(n²)` double loop,
    hence `Θ(n³)` operations.

    The cost is proportional to the number of edges in the transitive closure;
    for dense graphs this is `Θ(n⁴)`, but in terms of input size it is `Θ(n³)`.

    Space: The algorithm keeps a matrix of `n²` entries; therefore
    `Θ(n²)` auxiliary space (plus the input graph).

    Thus, for a directed graph with `n` vertices and an arbitrary number of edges,
    the time complexity of computing all-pairs reachability is O(n³),
    and it requires O(n²) additional memory.

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